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So what's the right amount of oil after adding all the tubing? Should it be just the standard oil capacity + new tubing volume? 

Webberstyle said:So what's the right amount of oil after adding all the tubing? Should it be just the standard oil capacity + new tubing volume?![]()
Webberstyle said:Dude, you wanna be on the team?![]()
well thank you! the bike in question was my f2 that i'd already put about 12k on before the pressurization of the airbox, so i was very familiar with it. at around speeds way lower, than what you think would matter the bike seemed more "revvy" and the throttle response was better. now i'll admit it wasn't huge, but it was there. wonder what that difference in air pressure does to the engine vaccum and air resistance??xtasie99 said:I have to say, you're one hell of a seat of the pants dyno.
xtasie99 said:P + (rho*V**2)/2 = constant
or:
Ps + q = Pt
where:
Ps = static pressure
q = dynamic pressure
Pt = total pressure
and:
q = (rho*V**2)/2
Assuming a standard day at sea level:
T = 59 degrees Fahrenheit
T = 518.69 degrees Rankine (Rankine = F + 459.67)
Ps = 2116.2 lb/ft**2 (=14.696 psi)
rho = 0.0023769 lb*sec**2/ft**4
At 40mph = 58.67ft/s
Pt = 2116.2 + .5*0.0023769*58.67^2
= 2116.2 + 4.09
= 2120.3 lb/ft^2
= 14.7242 PSI
So, assuming you have a perfect intake that completely stops the air and converts all dynamic pressure into static pressure (which isn't true, since the intake is sucking air) you make an additional .028 PSI of boost.
I have to say, you're one hell of a seat of the pants dyno.
that looks to me like you have the throttle body out in the wind with no 'funnel' in front of it. at high speeds, the funnel doesn't need to be that big; at low speeds, it would have to be much larger to produce the same "boost".xtasie99 said:P + (rho*V**2)/2 = constant
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You're welcome.Webberstyle said:...I found the adapters for the oil cooler, ... Thanks Steve!